What is (x+3)/(3-x)>= x/(x+1) ?

The solution to (x+3)/(3-x)>= x/(x+1) is -1<x<3

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(x+3)/(3-x)>= x/(x+1)

\frac{x + 3}{3 - x} \geq \frac{x}{x + 1}

- 1 < x < 3

Interval Notation

(- 1, 3)

Solution steps

\frac{x + 3}{3 - x} \geq \frac{x}{x + 1}

Rewrite in standard form

\frac{2 x ^{2} + x + 3}{( - x + 3 ) ( x + 1 )} \geq 0

Identify the intervals

- 1 < x < 3

f (k) = \frac{k ^{2} - 22 k + 121}{k ^{2} - 121}

2 + (- 2)

∣ v ∣ \leq 5

\frac{( 3 + 4 i )}{1 + 2 i}

13 x - 5 - 6 x = 9