What are the solutions to the equation 9x^2+4=12x ?

The solutions to the equation 9x^2+4=12x are x= 2/3

Find the zeros of 9x^2+4=12x

The zeros of 9x^2+4=12x are x= 2/3

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9 x^{2} + 4 = 12 x

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

9 x^{2} + 4 = 12 x

Move

12 x

to the left side

9 x^{2} + 4 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

2 x^{2} + x - 1 = 0

(x + 3)^{2} = 1

3 (60)

\frac{( 3 k ^{4} ) ^{5}}{- 15 k ^{10}}

5 (\frac{1}{2} x + 3) \leq 4 (\frac{1}{3} x + 5)

What are the solutions to the equation 9x^2+4=12x ?
The solutions to the equation 9x^2+4=12x are x= 2/3
Find the zeros of 9x^2+4=12x
The zeros of 9x^2+4=12x are x= 2/3