What are the solutions to the equation x^2-8x+8=-10 ?

The solutions to the equation x^2-8x+8=-10 are x=4+sqrt(2)i,x=4-sqrt(2)i

Find the zeros of x^2-8x+8=-10

The zeros of x^2-8x+8=-10 are x=4+sqrt(2)i,x=4-sqrt(2)i

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x^{2} - 8 x + 8 = - 10

x = 4 + 2 i, x = 4 - 2 i

Solution steps

x^{2} - 8 x + 8 = - 10

Move

10

to the left side

x^{2} - 8 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 18 : 22 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 1} : 4 + 2 i

x = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

x = 4 + 2 i, x = 4 - 2 i

\frac{2 x}{9} + \frac{5}{9} = \frac{x - 1}{9}

3 x + 5 = - 7 x - 9

5 x^{2} - x - 18

(- 1 + i) (- 1 - i)

(- 4 b^{3} + b - 1) + (6 b - 6)

What are the solutions to the equation x^2-8x+8=-10 ?
The solutions to the equation x^2-8x+8=-10 are x=4+sqrt(2)i,x=4-sqrt(2)i
Find the zeros of x^2-8x+8=-10
The zeros of x^2-8x+8=-10 are x=4+sqrt(2)i,x=4-sqrt(2)i