What are the solutions to the equation 4y^2-y+2=0 ?

The solutions to the equation 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8

Find the zeros of 4y^2-y+2=0

The zeros of 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8

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4 y^{2} - y + 2 = 0

y = \frac{1}{8} + i \frac{31}{8}, y = \frac{1}{8} - i \frac{31}{8}

Solution steps

4 y^{2} - y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 2 : 31 i

y_{1, 2} = \frac{- ( - 1 ) \pm 31 i}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 31 i}{2 \cdot 4}, y_{2} = \frac{- ( - 1 ) - 31 i}{2 \cdot 4}

y = \frac{- ( - 1 ) + 31 i}{2 \cdot 4} : \frac{1}{8} + i \frac{31}{8}

y = \frac{- ( - 1 ) - 31 i}{2 \cdot 4} : \frac{1}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

y = \frac{1}{8} + i \frac{31}{8}, y = \frac{1}{8} - i \frac{31}{8}

2 π (40) (0.04)

3 x + 1 = 2 x

x^{2} - 10 x y + 16 y^{2}

\frac{50}{50 - 4}

0.64 \cdot 5 + 18 \cdot 1600

What are the solutions to the equation 4y^2-y+2=0 ?
The solutions to the equation 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8
Find the zeros of 4y^2-y+2=0
The zeros of 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8