What are the solutions to the equation (((15-5x)/2)^2)+2.5(x)^2=27.5 ?

The solutions to the equation (((15-5x)/2)^2)+2.5(x)^2=27.5 are x= 23/7 ,x=1

Find the zeros of (((15-5x)/2)^2)+2.5(x)^2=27.5

The zeros of (((15-5x)/2)^2)+2.5(x)^2=27.5 are x= 23/7 ,x=1

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((\frac{15 - 5 x}{2})^{2}) + 2.5 (x)^{2} = 27.5

x = \frac{23}{7}, x = 1

Decimal Notation

x = 3.28571 \dots, x = 1

Solution steps

((\frac{15 - 5 x}{2})^{2}) + 2.5 x^{2} = 27.5

Multiply both sides by

10

\frac{5 ( - 5 x + 15 ) ^{2}}{2} + 25 x^{2} = 275

Multiply both sides by

2

5 (- 5 x + 15)^{2} + 50 x^{2} = 550

Expand

5 (- 5 x + 15)^{2} + 50 x^{2} : 175 x^{2} - 750 x + 1125

175 x^{2} - 750 x + 1125 = 550

Move

550

to the left side

175 x^{2} - 750 x + 575 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 750 ) \pm ( - 750 ) ^{2} - 4 \cdot 175 \cdot 575}{2 \cdot 175}

(- 750)^{2} - 4 \cdot 175 \cdot 575 = 400

x_{1, 2} = \frac{- ( - 750 ) \pm 400}{2 \cdot 175}

Separate the solutions

x_{1} = \frac{- ( - 750 ) + 400}{2 \cdot 175}, x_{2} = \frac{- ( - 750 ) - 400}{2 \cdot 175}

x = \frac{- ( - 750 ) + 400}{2 \cdot 175} : \frac{23}{7}

x = \frac{- ( - 750 ) - 400}{2 \cdot 175} : 1

The solutions to the quadratic equation are:

x = \frac{23}{7}, x = 1

x^{2} + (2 x + 4)^{2} = (2 x + 6)^{2}

∣ x - 3 ∣ = - 4

- \frac{12}{2 ( - 3 )}

5 x^{2} y - x^{2} + 5 y - 1

\frac{4 x ^{2} - 25}{x ^{2} - 9} \leq 0

What are the solutions to the equation (((15-5x)/2)^2)+2.5(x)^2=27.5 ?
The solutions to the equation (((15-5x)/2)^2)+2.5(x)^2=27.5 are x= 23/7 ,x=1
Find the zeros of (((15-5x)/2)^2)+2.5(x)^2=27.5
The zeros of (((15-5x)/2)^2)+2.5(x)^2=27.5 are x= 23/7 ,x=1