What are the solutions to the equation 4x^2-7=4x ?

The solutions to the equation 4x^2-7=4x are x=(1+2sqrt(2))/2 ,x=(1-2sqrt(2))/2

Find the zeros of 4x^2-7=4x

The zeros of 4x^2-7=4x are x=(1+2sqrt(2))/2 ,x=(1-2sqrt(2))/2

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4 x^{2} - 7 = 4 x

x = \frac{1 + 2 2}{2}, x = \frac{1 - 2 2}{2}

Solution steps

4 x^{2} - 7 = 4 x

Move

4 x

to the left side

4 x^{2} - 7 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 7) = 82

x_{1, 2} = \frac{- ( - 4 ) \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 2}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8 2}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8 2}{2 \cdot 4} : \frac{1 + 2 2}{2}

x = \frac{- ( - 4 ) - 8 2}{2 \cdot 4} : \frac{1 - 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 2 2}{2}, x = \frac{1 - 2 2}{2}

ln (e) + 1

- 6 w + 1 = - 11

\frac{x}{3} - 5 = 3

2 (3 v + 8) = 70

- 4 (7 + v) = 28

What are the solutions to the equation 4x^2-7=4x ?
The solutions to the equation 4x^2-7=4x are x=(1+2sqrt(2))/2 ,x=(1-2sqrt(2))/2
Find the zeros of 4x^2-7=4x
The zeros of 4x^2-7=4x are x=(1+2sqrt(2))/2 ,x=(1-2sqrt(2))/2