What is the answer to (x+3)^3-(3x-1)^2=x^3+4 ?

The answer to (x+3)^3-(3x-1)^2=x^3+4 is x=-2/3

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(x+3)^3-(3x-1)^2=x^3+4

(x + 3)^{3} - (3 x - 1)^{2} = x^{3} + 4

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

(x + 3)^{3} - (3 x - 1)^{2} = x^{3} + 4

Expand

(x + 3)^{3} - (3 x - 1)^{2} : x^{3} + 33 x + 26

x^{3} + 33 x + 26 = x^{3} + 4

Move

26

to the right side

x^{3} + 33 x = x^{3} - 22

Move

x^{3}

to the left side

33 x = - 22

Divide both sides by

33

x = - \frac{2}{3}

2 x^{- 4}

e^{x} \cdot e^{x}

f = 0.83 (4)^{2} - 3.32 (4) + 21.1

2 8^{\frac{1}{2}}

x - 2 < x (x - 4) < 5

What is the answer to (x+3)^3-(3x-1)^2=x^3+4 ?
The answer to (x+3)^3-(3x-1)^2=x^3+4 is x=-2/3
Solve for x: (x+3)^3-(3x-1)^2=x^3+4
The solution is x=-2/3