What are the solutions to the equation (5x-3)*(4x+7)=0 ?

The solutions to the equation (5x-3)*(4x+7)=0 are x= 3/5 ,x=-7/4

Find the zeros of (5x-3)*(4x+7)=0

The zeros of (5x-3)*(4x+7)=0 are x= 3/5 ,x=-7/4

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(5 x - 3) \cdot (4 x + 7) = 0

x = \frac{3}{5}, x = - \frac{7}{4}

Decimal Notation

x = 0.6, x = - 1.75

Solution steps

(5 x - 3) (4 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 3 = 0 or 4 x + 7 = 0

Solve

5 x - 3 = 0 : x = \frac{3}{5}

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{7}{4}

8 x \frac{2}{3} - 43 x \frac{1}{3} + 15 = 0

2 g > - 8

\frac{1}{a - b} - \frac{1}{b - a}

15 q^{3} + 40 q^{2} + 3 q + 8

What are the solutions to the equation (5x-3)*(4x+7)=0 ?
The solutions to the equation (5x-3)*(4x+7)=0 are x= 3/5 ,x=-7/4
Find the zeros of (5x-3)*(4x+7)=0
The zeros of (5x-3)*(4x+7)=0 are x= 3/5 ,x=-7/4