What are the solutions to the equation -2(x-1)^2=36 ?

The solutions to the equation -2(x-1)^2=36 are x=3sqrt(2)i+1,x=-3sqrt(2)i+1

Find the zeros of -2(x-1)^2=36

The zeros of -2(x-1)^2=36 are x=3sqrt(2)i+1,x=-3sqrt(2)i+1

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- 2 (x - 1)^{2} = 36

x = 32 i + 1, x = - 32 i + 1

Solution steps

- 2 (x - 1)^{2} = 36

Divide both sides by

- 2

(x - 1)^{2} = - 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 18 : x = 32 i + 1

Solve

x - 1 = - - 18 : x = - 32 i + 1

The solutions to the quadratic equation are:

x = 32 i + 1, x = - 32 i + 1

\frac{2 ( 9 ) ^{\frac{3}{2}}}{3}

\frac{( 12 x ^{2} y ^{6} ) ^{2}}{8 x ^{4} y ^{7}}

3 x \cdot 5 x = 5

- 130 = - 5 k

x^{2} = 3 x - 7

What are the solutions to the equation -2(x-1)^2=36 ?
The solutions to the equation -2(x-1)^2=36 are x=3sqrt(2)i+1,x=-3sqrt(2)i+1
Find the zeros of -2(x-1)^2=36
The zeros of -2(x-1)^2=36 are x=3sqrt(2)i+1,x=-3sqrt(2)i+1