What are the solutions to the equation d^2+8d-8=0 ?

The solutions to the equation d^2+8d-8=0 are d=2(sqrt(6)-2),d=-2(2+sqrt(6))

Find the zeros of d^2+8d-8=0

The zeros of d^2+8d-8=0 are d=2(sqrt(6)-2),d=-2(2+sqrt(6))

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d^{2} + 8 d - 8 = 0

d = 2 (6 - 2), d = - 2 (2 + 6)

Decimal Notation

d = 0.89897 \dots, d = - 8.89897 \dots

Solution steps

d^{2} + 8 d - 8 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 8) = 46

d_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 8 + 4 6}{2 \cdot 1}, d_{2} = \frac{- 8 - 4 6}{2 \cdot 1}

d = \frac{- 8 + 4 6}{2 \cdot 1} : 2 (6 - 2)

d = \frac{- 8 - 4 6}{2 \cdot 1} : - 2 (2 + 6)

The solutions to the quadratic equation are:

d = 2 (6 - 2), d = - 2 (2 + 6)

18 x + 33 - 6 x^{4} - 11 x^{3}

x^{5} + m^{5}

\frac{4}{4 ^{2} + 1}

\frac{y}{- 1} + 4 < 9.97

26 = 54 t - 5 t^{2}

What are the solutions to the equation d^2+8d-8=0 ?
The solutions to the equation d^2+8d-8=0 are d=2(sqrt(6)-2),d=-2(2+sqrt(6))
Find the zeros of d^2+8d-8=0
The zeros of d^2+8d-8=0 are d=2(sqrt(6)-2),d=-2(2+sqrt(6))