What are the solutions to the equation x^2+6x=-5 ?

The solutions to the equation x^2+6x=-5 are x=-1,x=-5

Find the zeros of x^2+6x=-5

The zeros of x^2+6x=-5 are x=-1,x=-5

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x^{2} + 6 x = - 5

x = - 1, x = - 5

Solution steps

x^{2} + 6 x = - 5

Move

5

to the left side

x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 \cdot 1}, x_{2} = \frac{- 6 - 4}{2 \cdot 1}

x = \frac{- 6 + 4}{2 \cdot 1} : - 1

x = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

(\frac{6}{- 4})^{2}

\frac{2 π}{\frac{1}{7}}

3 b^{2} - 36 b - 135

\frac{( 9 \cdot 1 0 ^{9} ) ( 444 \cdot 1 0 ^{- 12} )}{2}

- (- 2)^{2}

What are the solutions to the equation x^2+6x=-5 ?
The solutions to the equation x^2+6x=-5 are x=-1,x=-5
Find the zeros of x^2+6x=-5
The zeros of x^2+6x=-5 are x=-1,x=-5