What are the solutions to the equation 4u^2+12u=-9 ?

The solutions to the equation 4u^2+12u=-9 are u=-3/2

Find the zeros of 4u^2+12u=-9

The zeros of 4u^2+12u=-9 are u=-3/2

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4 u^{2} + 12 u = - 9

u = - \frac{3}{2}

Decimal Notation

u = - 1.5

Solution steps

4 u^{2} + 12 u = - 9

Move

9

to the left side

4 u^{2} + 12 u + 9 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

u_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

u = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

u = - \frac{3}{2}

The solution to the quadratic equation is:

u = - \frac{3}{2}

x - 4 \geq 6 x - 3 (x + 1)

x^{2} - 8 x = 2

0.5 \cdot 9.8

\frac{c ^{8} d ^{- 12}}{c ^{- 4} d ^{- 8}}

4 + 5 m = 4 m + 1 + m

What are the solutions to the equation 4u^2+12u=-9 ?
The solutions to the equation 4u^2+12u=-9 are u=-3/2
Find the zeros of 4u^2+12u=-9
The zeros of 4u^2+12u=-9 are u=-3/2