What are the solutions to the equation 0=(2.5+y)(1.8-y) ?

The solutions to the equation 0=(2.5+y)(1.8-y) are y=-2.5,y=1.8

Find the zeros of 0=(2.5+y)(1.8-y)

The zeros of 0=(2.5+y)(1.8-y) are y=-2.5,y=1.8

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0 = (2.5 + y) (1.8 - y)

y = - 2.5, y = 1.8

Solution steps

0 = (2.5 + y) (1.8 - y)

Switch sides

(2.5 + y) (1.8 - y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2.5 + y = 0 or 1.8 - y = 0

Solve

2.5 + y = 0 : y = - 2.5

Solve

1.8 - y = 0 : y = 1.8

The solutions to the quadratic equation are:

y = - 2.5, y = 1.8

(x^{a})^{b}

\frac{1}{x} < \frac{x}{x + 2}

(q^{9})^{2}

0.000189707 x^{2} + 0.982889 x + 0.0852592 = 0

w^{2} + 2 w - 24

What are the solutions to the equation 0=(2.5+y)(1.8-y) ?
The solutions to the equation 0=(2.5+y)(1.8-y) are y=-2.5,y=1.8
Find the zeros of 0=(2.5+y)(1.8-y)
The zeros of 0=(2.5+y)(1.8-y) are y=-2.5,y=1.8