What are the solutions to the equation 3x^2-x+5=0 ?

The solutions to the equation 3x^2-x+5=0 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6

Find the zeros of 3x^2-x+5=0

The zeros of 3x^2-x+5=0 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6

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3 x^{2} - x + 5 = 0

x = \frac{1}{6} + i \frac{59}{6}, x = \frac{1}{6} - i \frac{59}{6}

Solution steps

3 x^{2} - x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 5 : 59 i

x_{1, 2} = \frac{- ( - 1 ) \pm 59 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 59 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 59 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 59 i}{2 \cdot 3} : \frac{1}{6} + i \frac{59}{6}

x = \frac{- ( - 1 ) - 59 i}{2 \cdot 3} : \frac{1}{6} - i \frac{59}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{59}{6}, x = \frac{1}{6} - i \frac{59}{6}

(\frac{1}{8})^{- 4}

(\frac{3}{5})^{0}

- 3 x - 43 = - 100

- x + \frac{1}{5} + 5 x = \frac{41}{5}

- 4 < \frac{2 x - 1}{4} < 0

What are the solutions to the equation 3x^2-x+5=0 ?
The solutions to the equation 3x^2-x+5=0 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6
Find the zeros of 3x^2-x+5=0
The zeros of 3x^2-x+5=0 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6