What is the answer to 1-[2-(3-x)]=4x-(6+x) ?

The answer to 1-[2-(3-x)]=4x-(6+x) is x=2

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1-[2-(3-x)]=4x-(6+x)

1 - [2 - (3 - x)] = 4 x - (6 + x)

x = 2

Solution steps

1 - [2 - (3 - x)] = 4 x - (6 + x)

Expand

1 - (2 - (3 - x)) : - x + 2

Expand

4 x - (6 + x) : 3 x - 6

- x + 2 = 3 x - 6

Move

2

to the right side

- x = 3 x - 8

Move

3 x

to the left side

- 4 x = - 8

Divide both sides by

- 4

x = 2

(4 - 1)^{2}

3 z^{2} - 22 z + 7

\frac{1}{6} (2)

x^{2} - 10 x + 24

2 x^{2} - 12 x y - 32 y^{2}

What is the answer to 1-[2-(3-x)]=4x-(6+x) ?
The answer to 1-[2-(3-x)]=4x-(6+x) is x=2
Solve for x: 1-[2-(3-x)]=4x-(6+x)
The solution is x=2