What are the solutions to the equation 0=-4x^2+14x-7 ?

The solutions to the equation 0=-4x^2+14x-7 are x=(7-sqrt(21))/4 ,x=(7+sqrt(21))/4

Find the zeros of 0=-4x^2+14x-7

The zeros of 0=-4x^2+14x-7 are x=(7-sqrt(21))/4 ,x=(7+sqrt(21))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 4 x^{2} + 14 x - 7

x = \frac{7 - 21}{4}, x = \frac{7 + 21}{4}

Decimal Notation

x = 0.60435 \dots, x = 2.89564 \dots

Solution steps

0 = - 4 x^{2} + 14 x - 7

Switch sides

- 4 x^{2} + 14 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 4 ) ( - 7 )}{2 ( - 4 )}

1 4^{2} - 4 (- 4) (- 7) = 221

x_{1, 2} = \frac{- 14 \pm 2 21}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 14 + 2 21}{2 ( - 4 )}, x_{2} = \frac{- 14 - 2 21}{2 ( - 4 )}

x = \frac{- 14 + 2 21}{2 ( - 4 )} : \frac{7 - 21}{4}

x = \frac{- 14 - 2 21}{2 ( - 4 )} : \frac{7 + 21}{4}

The solutions to the quadratic equation are:

x = \frac{7 - 21}{4}, x = \frac{7 + 21}{4}

a^{2} + 15 ab + 56 b^{2}

75 p^{2} - 27

lo g_{10} (0.0001) = x

8 - (- 2 t + 1) < t + 5 - 7

x^{2} - 14 x + 33 \leq 0

What are the solutions to the equation 0=-4x^2+14x-7 ?
The solutions to the equation 0=-4x^2+14x-7 are x=(7-sqrt(21))/4 ,x=(7+sqrt(21))/4
Find the zeros of 0=-4x^2+14x-7
The zeros of 0=-4x^2+14x-7 are x=(7-sqrt(21))/4 ,x=(7+sqrt(21))/4