What are the solutions to the equation 4b(b+4)=0 ?

The solutions to the equation 4b(b+4)=0 are b=0,b=-4

Find the zeros of 4b(b+4)=0

The zeros of 4b(b+4)=0 are b=0,b=-4

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4 b (b + 4) = 0

b = 0, b = - 4

Solution steps

4 b (b + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or b + 4 = 0

Solve

b + 4 = 0 : b = - 4

The solutions to the quadratic equation are:

b = 0, b = - 4

(\frac{25}{36})^{- \frac{1}{2}}

x^{3} - 4 x

\frac{2}{3} x^{2} = 24

\frac{7}{5} + \frac{4}{9} - \frac{3}{8}

x - (7 x - 3) < 7 - 4 x - 5

What are the solutions to the equation 4b(b+4)=0 ?
The solutions to the equation 4b(b+4)=0 are b=0,b=-4
Find the zeros of 4b(b+4)=0
The zeros of 4b(b+4)=0 are b=0,b=-4