What is (2n^{1/3}(3n^{1/3}-4n^{4/3}))/(2n^{-1/3)} ?

The solution to (2n^{1/3}(3n^{1/3}-4n^{4/3}))/(2n^{-1/3)} is n^{2/3}(3n^{1/3}-4n^{4/3})

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simplify (2n^{1/3}(3n^{1/3}-4n^{4/3}))/(2n^{-1/3)}

simplify

\frac{2 n ^{\frac{1}{3}} ( 3 n ^{\frac{1}{3}} - 4 n ^{\frac{4}{3}} )}{2 n ^{- \frac{1}{3}}}

n^{\frac{2}{3}} (3 n^{\frac{1}{3}} - 4 n^{\frac{4}{3}})

Solution steps

\frac{2 n ^{\frac{1}{3}} ( 3 n ^{\frac{1}{3}} - 4 n ^{\frac{4}{3}} )}{2 n ^{- \frac{1}{3}}}

Cancel the common factor:

2

= \frac{n ^{\frac{1}{3}} ( 3 n ^{\frac{1}{3}} - 4 n ^{\frac{4}{3}} )}{n ^{- \frac{1}{3}}}

Simplify

\frac{n ^{\frac{1}{3}}}{n ^{- \frac{1}{3}}} : n^{\frac{2}{3}}

= n^{\frac{2}{3}} (3 n^{\frac{1}{3}} - 4 n^{\frac{4}{3}})

- 1 (- 4)

- 2 (6 x - 3)^{2} - 12 = - 48

42 z^{2} - zy - y^{2}

2 x^{2} = 5

x^{2} - 3 x + 5 = 0

What is (2n^{1/3}(3n^{1/3}-4n^{4/3}))/(2n^{-1/3)} ?
The solution to (2n^{1/3}(3n^{1/3}-4n^{4/3}))/(2n^{-1/3)} is n^{2/3}(3n^{1/3}-4n^{4/3})