What is 9-4x>= 5\lor 4(-1+x)-6>= 2 ?

The solution to 9-4x>= 5\lor 4(-1+x)-6>= 2 is x = 3

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9-4x>= 5\lor 4(-1+x)-6>= 2

9 - 4 x \geq 5 or 4 (- 1 + x) - 6 \geq 2

x \leq 1 or x \geq 3

Interval Notation

(- \infty, 1] \cup [3, \infty)

Solution steps

9 - 4 x \geq 5 or 4 (- 1 + x) - 6 \geq 2

9 - 4 x \geq 5 : x \leq 1

4 (- 1 + x) - 6 \geq 2 : x \geq 3

Combine the intervals

x \leq 1 or x \geq 3

\frac{5 ! 6 !}{3 ! 8 !}

x^{2} + 12 x + 11

\frac{1 2 ^{5}}{1 2 ^{3}}

5 x - 4 = x

x^{4} - 3 x^{3} - 4

What is 9-4x>= 5\lor 4(-1+x)-6>= 2 ?
The solution to 9-4x>= 5\lor 4(-1+x)-6>= 2 is x<= 1\lor x>= 3