What are the solutions to the equation -3X^2-3X+10=0 ?

The solutions to the equation -3X^2-3X+10=0 are X=-(3+sqrt(129))/6 ,X=(sqrt(129)-3)/6

Find the zeros of -3X^2-3X+10=0

The zeros of -3X^2-3X+10=0 are X=-(3+sqrt(129))/6 ,X=(sqrt(129)-3)/6

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- 3 X^{2} - 3 X + 10 = 0

X = - \frac{3 + 129}{6}, X = \frac{129 - 3}{6}

Decimal Notation

X = - 2.39296 \dots, X = 1.39296 \dots

Solution steps

- 3 X^{2} - 3 X + 10 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 3 ) \cdot 10}{2 ( - 3 )}

(- 3)^{2} - 4 (- 3) \cdot 10 = 129

X_{1, 2} = \frac{- ( - 3 ) \pm 129}{2 ( - 3 )}

Separate the solutions

X_{1} = \frac{- ( - 3 ) + 129}{2 ( - 3 )}, X_{2} = \frac{- ( - 3 ) - 129}{2 ( - 3 )}

X = \frac{- ( - 3 ) + 129}{2 ( - 3 )} : - \frac{3 + 129}{6}

X = \frac{- ( - 3 ) - 129}{2 ( - 3 )} : \frac{129 - 3}{6}

The solutions to the quadratic equation are:

X = - \frac{3 + 129}{6}, X = \frac{129 - 3}{6}

4 w - 8 = 32

2 7^{\frac{3}{2}}

x^{2} \leq 81

(p + 1)^{2} + 5 (p + 1) = 0

2 r \leq - 8

What are the solutions to the equation -3X^2-3X+10=0 ?
The solutions to the equation -3X^2-3X+10=0 are X=-(3+sqrt(129))/6 ,X=(sqrt(129)-3)/6
Find the zeros of -3X^2-3X+10=0
The zeros of -3X^2-3X+10=0 are X=-(3+sqrt(129))/6 ,X=(sqrt(129)-3)/6