What is ((9x-11)(2x+7))/((3x-8)^3)>0 ?

The solution to ((9x-11)(2x+7))/((3x-8)^3)>0 is -7/2 8/3

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((9x-11)(2x+7))/((3x-8)^3)>0

\frac{( 9 x - 11 ) ( 2 x + 7 )}{( 3 x - 8 ) ^{3}} > 0

- \frac{7}{2} < x < \frac{11}{9} or x > \frac{8}{3}

Interval Notation

(- \frac{7}{2}, \frac{11}{9}) \cup (\frac{8}{3}, \infty)

Decimal Notation

- 3.5 < x < 1.22222 \dots or x > 2.66666 \dots

Solution steps

\frac{( 9 x - 11 ) ( 2 x + 7 )}{( 3 x - 8 ) ^{3}} > 0

Identify the intervals

- \frac{7}{2} < x < \frac{11}{9} or x > \frac{8}{3}

∣ 7 x + 28 ∣ = 0

s^{2} + 12 s - 13

\frac{5}{13} = t - \frac{6}{13}

4 x^{2} + 16 x + 25 = 0

1 - 3 x = 4 x - 6

What is ((9x-11)(2x+7))/((3x-8)^3)>0 ?
The solution to ((9x-11)(2x+7))/((3x-8)^3)>0 is -7/2 <x< 11/9 \lor x> 8/3