What are the solutions to the equation -5+2x^2=-6x ?

The solutions to the equation -5+2x^2=-6x are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

Find the zeros of -5+2x^2=-6x

The zeros of -5+2x^2=-6x are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

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- 5 + 2 x^{2} = - 6 x

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

Decimal Notation

x = 0.67944 \dots, x = - 3.67944 \dots

Solution steps

- 5 + 2 x^{2} = - 6 x

Move

6 x

to the left side

- 5 + 2 x^{2} + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 5) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 2}

x = \frac{- 6 + 2 19}{2 \cdot 2} : \frac{- 3 + 19}{2}

x = \frac{- 6 - 2 19}{2 \cdot 2} : - \frac{3 + 19}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

5 x = - 7 x - 48

5.1 x = - 22.44

8 - 4 x = 0

4 v^{4} + 16 v^{2}

2 = lo g_{9} (3)

What are the solutions to the equation -5+2x^2=-6x ?
The solutions to the equation -5+2x^2=-6x are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2
Find the zeros of -5+2x^2=-6x
The zeros of -5+2x^2=-6x are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2