What are the solutions to the equation d^2+9=0 ?

The solutions to the equation d^2+9=0 are d=3i,d=-3i

Find the zeros of d^2+9=0

The zeros of d^2+9=0 are d=3i,d=-3i

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d^{2} + 9 = 0

d = 3 i, d = - 3 i

Solution steps

d^{2} + 9 = 0

Move

9

to the right side

d^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = - 9, d = - - 9

- 9 = 3 i

- - 9 = - 3 i

d = 3 i, d = - 3 i

7 x^{2} - 28 x = 0

\frac{k}{2} > 4

3 h + 7 \geq - h - 10

(4)^{- 3}

(\frac{3 x ^{\frac{1}{2}}}{15})^{2}

What are the solutions to the equation d^2+9=0 ?
The solutions to the equation d^2+9=0 are d=3i,d=-3i
Find the zeros of d^2+9=0
The zeros of d^2+9=0 are d=3i,d=-3i