What are the solutions to the equation x*(x+1)=440 ?

The solutions to the equation x*(x+1)=440 are x=(-1+sqrt(1761))/2 ,x=(-1-sqrt(1761))/2

Find the zeros of x*(x+1)=440

The zeros of x*(x+1)=440 are x=(-1+sqrt(1761))/2 ,x=(-1-sqrt(1761))/2

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x \cdot (x + 1) = 440

x = \frac{- 1 + 1761}{2}, x = \frac{- 1 - 1761}{2}

Decimal Notation

x = 20.48213 \dots, x = - 21.48213 \dots

Solution steps

x (x + 1) = 440

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 440

Move

440

to the left side

x^{2} + x - 440 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 440 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 440) = 1761

x_{1, 2} = \frac{- 1 \pm 1761}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1761}{2 \cdot 1}, x_{2} = \frac{- 1 - 1761}{2 \cdot 1}

x = \frac{- 1 + 1761}{2 \cdot 1} : \frac{- 1 + 1761}{2}

x = \frac{- 1 - 1761}{2 \cdot 1} : \frac{- 1 - 1761}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 1761}{2}, x = \frac{- 1 - 1761}{2}

\frac{3 + 5}{3 - 5}

0. 6^{4}

4 m - 4 - 8 = - 2 m + 12

\frac{7}{12} + \frac{5}{8}

4 (x + 3) - (1 - x) = 1

What are the solutions to the equation x*(x+1)=440 ?
The solutions to the equation x*(x+1)=440 are x=(-1+sqrt(1761))/2 ,x=(-1-sqrt(1761))/2
Find the zeros of x*(x+1)=440
The zeros of x*(x+1)=440 are x=(-1+sqrt(1761))/2 ,x=(-1-sqrt(1761))/2