What are the solutions to the equation x^2+6=-7x ?

The solutions to the equation x^2+6=-7x are x=-1,x=-6

Find the zeros of x^2+6=-7x

The zeros of x^2+6=-7x are x=-1,x=-6

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x^{2} + 6 = - 7 x

x = - 1, x = - 6

Solution steps

x^{2} + 6 = - 7 x

Move

7 x

to the left side

x^{2} + 6 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : - 1

x = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

12 n p - 3 p + 8 n - 2

1 0^{2} + 10 0^{\frac{1}{2}} + 10 0^{0}

\frac{9 c ^{3}}{c ^{- 4}}

(- 3)^{4}

7 z^{2} - 20 z - 3

What are the solutions to the equation x^2+6=-7x ?
The solutions to the equation x^2+6=-7x are x=-1,x=-6
Find the zeros of x^2+6=-7x
The zeros of x^2+6=-7x are x=-1,x=-6