What are the solutions to the equation 16x^2-8x+6=5 ?

The solutions to the equation 16x^2-8x+6=5 are x= 1/4

Find the zeros of 16x^2-8x+6=5

The zeros of 16x^2-8x+6=5 are x= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} - 8 x + 6 = 5

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

16 x^{2} - 8 x + 6 = 5

Move

5

to the left side

16 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

(- 8)^{2} - 4 \cdot 16 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 8 )}{2 \cdot 16}

\frac{- ( - 8 )}{2 \cdot 16} = \frac{1}{4}

x = \frac{1}{4}

The solution to the quadratic equation is:

x = \frac{1}{4}

- 3 x^{3} - 12 x^{2} - 3 x + 18 \geq 0

\frac{2}{\frac{6}{7}}

(\frac{3}{5})^{2}

14 s^{4} - 19 s^{2} r^{2} + 5 r^{4}

20 e^{5} f^{2} - 16 e^{2} f

What are the solutions to the equation 16x^2-8x+6=5 ?
The solutions to the equation 16x^2-8x+6=5 are x= 1/4
Find the zeros of 16x^2-8x+6=5
The zeros of 16x^2-8x+6=5 are x= 1/4