What are the solutions to the equation 4v^2+3v-1=0 ?

The solutions to the equation 4v^2+3v-1=0 are v= 1/4 ,v=-1

Find the zeros of 4v^2+3v-1=0

The zeros of 4v^2+3v-1=0 are v= 1/4 ,v=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 v^{2} + 3 v - 1 = 0

v = \frac{1}{4}, v = - 1

Decimal Notation

v = 0.25, v = - 1

Solution steps

4 v^{2} + 3 v - 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 1) = 5

v_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- 3 + 5}{2 \cdot 4}, v_{2} = \frac{- 3 - 5}{2 \cdot 4}

v = \frac{- 3 + 5}{2 \cdot 4} : \frac{1}{4}

v = \frac{- 3 - 5}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

v = \frac{1}{4}, v = - 1

y^{2} - 8 y + 17 = 0

x^{2} = 4 x - 20

ln (36)

5 x = 6 x^{2} - 3

60 (1 0^{6}) = \frac{( - 900 + x ) ( 0.025 )}{( \frac{π}{2} ) ( 0.02 5 ^{4} )}

What are the solutions to the equation 4v^2+3v-1=0 ?
The solutions to the equation 4v^2+3v-1=0 are v= 1/4 ,v=-1
Find the zeros of 4v^2+3v-1=0
The zeros of 4v^2+3v-1=0 are v= 1/4 ,v=-1