What is the answer to (x)(1*10^{-2})=(1*10^{-3})(25) ?

The answer to (x)(1*10^{-2})=(1*10^{-3})(25) is x= 5/2

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(x)(110^{-2})=(110^{-3})(25)

(x) (1 \cdot 1 0^{- 2}) = (1 \cdot 1 0^{- 3}) (25)

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

(x) (1 \cdot 1 0^{- 2}) = (1 \cdot 1 0^{- 3}) (25)

Simplify

(1 \cdot 1 0^{- 3}) (25) : \frac{1}{5 \cdot 2 ^{3}}

(x) (1 \cdot 1 0^{- 2}) = \frac{1}{5 \cdot 2 ^{3}}

Simplify

1 \cdot 1 0^{- 2} : \frac{1}{100}

x \frac{1}{100} = \frac{1}{5 \cdot 2 ^{3}}

Multiply both sides by

100

x = \frac{5}{2}

3^{n} + 3^{n}

20 x^{2} + 11 x = 3

\frac{- 1 + 17 i}{- 9 + 8 i}

1 - 10 n^{2} = - 89

What is the answer to (x)(1*10^{-2})=(1*10^{-3})(25) ?
The answer to (x)(1*10^{-2})=(1*10^{-3})(25) is x= 5/2
Solve for x: (x)(1*10^{-2})=(1*10^{-3})(25)
The solution is x= 5/2