What are the solutions to the equation -5x^2+9x=4 ?

The solutions to the equation -5x^2+9x=4 are x= 4/5 ,x=1

Find the zeros of -5x^2+9x=4

The zeros of -5x^2+9x=4 are x= 4/5 ,x=1

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- 5 x^{2} + 9 x = 4

x = \frac{4}{5}, x = 1

Decimal Notation

x = 0.8, x = 1

Solution steps

- 5 x^{2} + 9 x = 4

Move

4

to the left side

- 5 x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

9^{2} - 4 (- 5) (- 4) = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 ( - 5 )}, x_{2} = \frac{- 9 - 1}{2 ( - 5 )}

x = \frac{- 9 + 1}{2 ( - 5 )} : \frac{4}{5}

x = \frac{- 9 - 1}{2 ( - 5 )} : 1

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = 1

(x + 3) (x - 1) (x - 6) < 0

∣ - 25 ∣

- 15 = - 4 m + 5

- \frac{2}{3} \cdot \frac{1}{3}

What are the solutions to the equation -5x^2+9x=4 ?
The solutions to the equation -5x^2+9x=4 are x= 4/5 ,x=1
Find the zeros of -5x^2+9x=4
The zeros of -5x^2+9x=4 are x= 4/5 ,x=1