What are the solutions to the equation 4y^2-81=0 ?

The solutions to the equation 4y^2-81=0 are y= 9/2 ,y=-9/2

Find the zeros of 4y^2-81=0

The zeros of 4y^2-81=0 are y= 9/2 ,y=-9/2

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4 y^{2} - 81 = 0

y = \frac{9}{2}, y = - \frac{9}{2}

Decimal Notation

y = 4.5, y = - 4.5

Solution steps

4 y^{2} - 81 = 0

Move

81

to the right side

4 y^{2} = 81

Divide both sides by

4

y^{2} = \frac{81}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{81}{4}, y = - \frac{81}{4}

\frac{81}{4} = \frac{9}{2}

- \frac{81}{4} = - \frac{9}{2}

y = \frac{9}{2}, y = - \frac{9}{2}

y^{2} = 6 y + 16

- 3 + 7

3 (5 x - 6) (3 x + 2) - 6 (3 x + 4) (x - 1) - 3 (9 x + 1) (x - 2) = 0

5 \cdot 5 \cdot 5 \cdot 5 \cdot 5

7 ∣ 10 v - 2 ∣ - 9 = 5

What are the solutions to the equation 4y^2-81=0 ?
The solutions to the equation 4y^2-81=0 are y= 9/2 ,y=-9/2
Find the zeros of 4y^2-81=0
The zeros of 4y^2-81=0 are y= 9/2 ,y=-9/2