What are the solutions to the equation -3x^2+108=0 ?

The solutions to the equation -3x^2+108=0 are x=6,x=-6

Find the zeros of -3x^2+108=0

The zeros of -3x^2+108=0 are x=6,x=-6

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- 3 x^{2} + 108 = 0

x = 6, x = - 6

Solution steps

- 3 x^{2} + 108 = 0

Move

108

to the right side

- 3 x^{2} = - 108

Divide both sides by

- 3

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

(\frac{1}{2})^{3} \cdot (\frac{3}{2})^{- 2}

- 8 > \frac{12}{7} u

7^{3} \cdot 7^{5}

∣ 4 x + 2 ∣ - 3 \geq 11

\frac{4 p + 8 q}{p ^{2} + 2 pq}

What are the solutions to the equation -3x^2+108=0 ?
The solutions to the equation -3x^2+108=0 are x=6,x=-6
Find the zeros of -3x^2+108=0
The zeros of -3x^2+108=0 are x=6,x=-6