What is -8x^2-10x+3<= 0 ?

The solution to -8x^2-10x+3 = 1/4

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-8x^2-10x+3<= 0

- 8 x^{2} - 10 x + 3 \leq 0

x \leq - \frac{3}{2} or x \geq \frac{1}{4}

Interval Notation

(- \infty, - \frac{3}{2}] \cup [\frac{1}{4}, \infty)

Decimal Notation

x \leq - 1.5 or x \geq 0.25

Solution steps

- 8 x^{2} - 10 x + 3 \leq 0

Factor

- 8 x^{2} - 10 x + 3 : - (4 x - 1) (2 x + 3)

- (4 x - 1) (2 x + 3) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (4 x - 1) (2 x + 3)) (- 1) \geq 0 \cdot (- 1)

Simplify

(4 x - 1) (2 x + 3) \geq 0

Identify the intervals

x \leq - \frac{3}{2} or x \geq \frac{1}{4}

\frac{105 - 84}{84}

(16 x^{8})^{\frac{1}{4}}

2 - 9 ∣ p + 7 ∣ \geq - 16

15 r^{2} + 2 rs - s^{2}

\frac{1}{27} x - \frac{4}{9} = \frac{2}{3}

What is -8x^2-10x+3<= 0 ?
The solution to -8x^2-10x+3<= 0 is x<=-3/2 \lor x>= 1/4