What are the solutions to the equation 15^2+17^2=c^2 ?

The solutions to the equation 15^2+17^2=c^2 are c=sqrt(514),c=-sqrt(514)

Find the zeros of 15^2+17^2=c^2

The zeros of 15^2+17^2=c^2 are c=sqrt(514),c=-sqrt(514)

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1 5^{2} + 1 7^{2} = c^{2}

c = 514, c = - 514

Decimal Notation

c = 22.67156 \dots, c = - 22.67156 \dots

Solution steps

1 5^{2} + 1 7^{2} = c^{2}

Switch sides

c^{2} = 1 5^{2} + 1 7^{2}

Simplify

1 5^{2} + 1 7^{2} : 514

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 514, c = - 514

7 (a + 3) + 21 = 91

\frac{( 3 x + 1 ) ^{2} ( x - 1 )}{1 - x ^{3}}

i^{61}

4 x + 5 < 21

(x + 7)^{3} x - 2 (x + 7)^{2} x^{2} + x^{3} (x + 7)

What are the solutions to the equation 15^2+17^2=c^2 ?
The solutions to the equation 15^2+17^2=c^2 are c=sqrt(514),c=-sqrt(514)
Find the zeros of 15^2+17^2=c^2
The zeros of 15^2+17^2=c^2 are c=sqrt(514),c=-sqrt(514)