What is 2<= (5x+3)/3 <= 4 ?

The solution to 2<= (5x+3)/3 <= 4 is 3/5 <= x<= 9/5

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2<= (5x+3)/3 <= 4

2 \leq \frac{5 x + 3}{3} \leq 4

\frac{3}{5} \leq x \leq \frac{9}{5}

Interval Notation

[\frac{3}{5}, \frac{9}{5}]

Decimal Notation

0.6 \leq x \leq 1.8

Solution steps

2 \leq \frac{5 x + 3}{3} \leq 4

a \leq u \leq b

then

a \leq u and u \leq b

2 \leq \frac{5 x + 3}{3} and \frac{5 x + 3}{3} \leq 4

2 \leq \frac{5 x + 3}{3} : x \geq \frac{3}{5}

\frac{5 x + 3}{3} \leq 4 : x \leq \frac{9}{5}

Combine the intervals

x \geq \frac{3}{5} and x \leq \frac{9}{5}

Merge Overlapping Intervals

\frac{3}{5} \leq x \leq \frac{9}{5}

\frac{k}{4} + 3 = 14

x^{2} + 5 x^{2} + 4 x

8 b^{2} - 7 = 193

∣ x - 2 ∣ = \frac{1}{4}

3 x^{2} - 11 x - 20