What are the solutions to the equation x^2+16x+62=0 ?

The solutions to the equation x^2+16x+62=0 are x=-8+sqrt(2),x=-8-sqrt(2)

Find the zeros of x^2+16x+62=0

The zeros of x^2+16x+62=0 are x=-8+sqrt(2),x=-8-sqrt(2)

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x^{2} + 16 x + 62 = 0

x = - 8 + 2, x = - 8 - 2

Solution steps

x^{2} + 16 x + 62 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 62}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 62 = 22

x_{1, 2} = \frac{- 16 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 2}{2 \cdot 1}

x = \frac{- 16 + 2 2}{2 \cdot 1} : - 8 + 2

x = \frac{- 16 - 2 2}{2 \cdot 1} : - 8 - 2

The solutions to the quadratic equation are:

x = - 8 + 2, x = - 8 - 2

4 (v - 4) (v + 1) = 0

3 x^{2} - 24 x + 48

- 65 y + 19 < - 2 y + 41

\frac{\frac{6}{7}}{6}

\frac{- 4 + 6 i}{2 + 7 i}

What are the solutions to the equation x^2+16x+62=0 ?
The solutions to the equation x^2+16x+62=0 are x=-8+sqrt(2),x=-8-sqrt(2)
Find the zeros of x^2+16x+62=0
The zeros of x^2+16x+62=0 are x=-8+sqrt(2),x=-8-sqrt(2)