What is (b^2+3b-28)/(b^2-49) ?

The solution to (b^2+3b-28)/(b^2-49) is (b-4)/(b-7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (b^2+3b-28)/(b^2-49)

simplify

\frac{b ^{2} + 3 b - 28}{b ^{2} - 49}

\frac{b - 4}{b - 7}

Solution steps

\frac{b ^{2} + 3 b - 28}{b ^{2} - 49}

Factor

b^{2} + 3 b - 28 : (b - 4) (b + 7)

= \frac{( b - 4 ) ( b + 7 )}{b ^{2} - 49}

Factor

b^{2} - 49 : (b + 7) (b - 7)

= \frac{( b - 4 ) ( b + 7 )}{( b + 7 ) ( b - 7 )}

Cancel the common factor:

b + 7

= \frac{b - 4}{b - 7}

x^{2} - 8 x + 8 = 0

\frac{1}{5} n + 8 \leq 95

9 x^{2} + 9 x y + 9 y^{2}

25 + 45 + 180 - 80

- \frac{2}{9} \cdot \frac{3}{10}

What is (b^2+3b-28)/(b^2-49) ?
The solution to (b^2+3b-28)/(b^2-49) is (b-4)/(b-7)