What are the solutions to the equation -3x^2+30x-48=0 ?

The solutions to the equation -3x^2+30x-48=0 are x=2,x=8

Find the zeros of -3x^2+30x-48=0

The zeros of -3x^2+30x-48=0 are x=2,x=8

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- 3 x^{2} + 30 x - 48 = 0

x = 2, x = 8

Solution steps

- 3 x^{2} + 30 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 3 ) ( - 48 )}{2 ( - 3 )}

3 0^{2} - 4 (- 3) (- 48) = 18

x_{1, 2} = \frac{- 30 \pm 18}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 30 + 18}{2 ( - 3 )}, x_{2} = \frac{- 30 - 18}{2 ( - 3 )}

x = \frac{- 30 + 18}{2 ( - 3 )} : 2

x = \frac{- 30 - 18}{2 ( - 3 )} : 8

The solutions to the quadratic equation are:

x = 2, x = 8

50 s^{10} + 10 s^{7}

\frac{3.99}{3.99 - 4}

- 5 < 1 - 2 x < 40

4 ∣ x + 2 ∣ \geq 16

50 - 6 x = 60 - 8 x

What are the solutions to the equation -3x^2+30x-48=0 ?
The solutions to the equation -3x^2+30x-48=0 are x=2,x=8
Find the zeros of -3x^2+30x-48=0
The zeros of -3x^2+30x-48=0 are x=2,x=8