What are the solutions to the equation y^2+15y+44=0 ?

The solutions to the equation y^2+15y+44=0 are y=-4,y=-11

Find the zeros of y^2+15y+44=0

The zeros of y^2+15y+44=0 are y=-4,y=-11

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y^{2} + 15 y + 44 = 0

y = - 4, y = - 11

Solution steps

y^{2} + 15 y + 44 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 44 = 7

y_{1, 2} = \frac{- 15 \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 15 + 7}{2 \cdot 1}, y_{2} = \frac{- 15 - 7}{2 \cdot 1}

y = \frac{- 15 + 7}{2 \cdot 1} : - 4

y = \frac{- 15 - 7}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

y = - 4, y = - 11

x^{2} = 120

\frac{11 k}{55 k ^{2} + 22 k}

(81)^{- \frac{1}{2}}

25 p + 50 q

ln ∣ - 1 ∣

What are the solutions to the equation y^2+15y+44=0 ?
The solutions to the equation y^2+15y+44=0 are y=-4,y=-11
Find the zeros of y^2+15y+44=0
The zeros of y^2+15y+44=0 are y=-4,y=-11