What are the solutions to the equation (5m+4)^2=0 ?

The solutions to the equation (5m+4)^2=0 are m=-4/5

Find the zeros of (5m+4)^2=0

The zeros of (5m+4)^2=0 are m=-4/5

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(5 m + 4)^{2} = 0

m = - \frac{4}{5}

Decimal Notation

m = - 0.8

Solution steps

(5 m + 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

5 m + 4 = 0 : m = - \frac{4}{5}

The solution to the quadratic equation is:

m = - \frac{4}{5}

z^{2} + 5 z + 2 = 0

2 x - 7 = - 17

\frac{1 0 ^{- 2}}{1 0 ^{- 14}}

\frac{x ^{3} y ^{5}}{x ^{10} y ^{4}}

x^{2} - 10 x - 20 = 0

What are the solutions to the equation (5m+4)^2=0 ?
The solutions to the equation (5m+4)^2=0 are m=-4/5
Find the zeros of (5m+4)^2=0
The zeros of (5m+4)^2=0 are m=-4/5