What is factor b^2+9b+18 ?

The solution to factor b^2+9b+18 is (b+3)(b+6)

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factor b^2+9b+18

factor

b^{2} + 9 b + 18

(b + 3) (b + 6)

Solution steps

b^{2} + 9 b + 18

Break the expression into groups

= (b^{2} + 3 b) + (6 b + 18)

Factor out

b

from

b^{2} + 3 b : b (b + 3)

Factor out

6

from

6 b + 18 : 6 (b + 3)

= b (b + 3) + 6 (b + 3)

Factor out common term

b + 3

= (b + 3) (b + 6)

(8 y^{3})^{- \frac{2}{3}}

\frac{1}{4} x^{2} + 2 x + 1 = 0

81 x^{2} - 18 x + 1 < 0

3 + 5 x - 10 = 3 x + 9

3 = x + 3