What are the solutions to the equation 4x^2+3x-22=0 ?

The solutions to the equation 4x^2+3x-22=0 are x=2,x=-11/4

Find the zeros of 4x^2+3x-22=0

The zeros of 4x^2+3x-22=0 are x=2,x=-11/4

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4 x^{2} + 3 x - 22 = 0

x = 2, x = - \frac{11}{4}

Decimal Notation

x = 2, x = - 2.75

Solution steps

4 x^{2} + 3 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 22 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 22) = 19

x_{1, 2} = \frac{- 3 \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 19}{2 \cdot 4}, x_{2} = \frac{- 3 - 19}{2 \cdot 4}

x = \frac{- 3 + 19}{2 \cdot 4} : 2

x = \frac{- 3 - 19}{2 \cdot 4} : - \frac{11}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{11}{4}

4 (6 x - 10) = 2 (20 x - 12)

1 < x and x > 13

3 x^{5} + 7 x

\frac{\frac{4 π}{3}}{4}

\frac{( 3 r ^{- 2} s ^{3} t ^{0} ) ^{- 3}}{3 rs}

What are the solutions to the equation 4x^2+3x-22=0 ?
The solutions to the equation 4x^2+3x-22=0 are x=2,x=-11/4
Find the zeros of 4x^2+3x-22=0
The zeros of 4x^2+3x-22=0 are x=2,x=-11/4