What are the solutions to the equation 3x^2+15x+18=0 ?

The solutions to the equation 3x^2+15x+18=0 are x=-2,x=-3

Find the zeros of 3x^2+15x+18=0

The zeros of 3x^2+15x+18=0 are x=-2,x=-3

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3 x^{2} + 15 x + 18 = 0

x = - 2, x = - 3

Solution steps

3 x^{2} + 15 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 \cdot 18 = 3

x_{1, 2} = \frac{- 15 \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 3}{2 \cdot 3}, x_{2} = \frac{- 15 - 3}{2 \cdot 3}

x = \frac{- 15 + 3}{2 \cdot 3} : - 2

x = \frac{- 15 - 3}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

x^{2} + 14 x = - 24

8 \cdot \frac{0.0289}{π ^{2} \cdot 9.81}

\frac{x}{3} = 4

- \frac{2}{2} \cdot \frac{1}{2}

- 3 x^{2} + 3 x - 2 = 0

What are the solutions to the equation 3x^2+15x+18=0 ?
The solutions to the equation 3x^2+15x+18=0 are x=-2,x=-3
Find the zeros of 3x^2+15x+18=0
The zeros of 3x^2+15x+18=0 are x=-2,x=-3