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Popular >

(1/27)^{2d-2}<= 81^{d+4}

Solution

(\frac{1}{27})^{2 d - 2} \leq 8 1^{d + 4}

Solution

d \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

(\frac{1}{27})^{2 d - 2} \leq 8 1^{d + 4}

If

f (x) \leq g (x)

then

ln (f (x)) \leq ln (g (x))

ln ((\frac{1}{27})^{2 d - 2}) \leq ln (8 1^{d + 4})

Simplify

ln ((\frac{1}{27})^{2 d - 2}) : - 3 ln (3) (2 d - 2)

Simplify

ln (8 1^{d + 4}) : 4 ln (3) (d + 4)

- 3 ln (3) (2 d - 2) \leq 4 ln (3) (d + 4)

- 3 ln (3) (2 d - 2) \leq 4 ln (3) (d + 4) : d \geq - 1

d \geq - 1

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Frequently Asked Questions (FAQ)

What is (1/27)^{2d-2}<= 81^{d+4} ?
The solution to (1/27)^{2d-2}<= 81^{d+4} is d>=-1