What are the solutions to the equation 4x^2-5x=2 ?

The solutions to the equation 4x^2-5x=2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

Find the zeros of 4x^2-5x=2

The zeros of 4x^2-5x=2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 5 x = 2

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

Decimal Notation

x = 1.56872 \dots, x = - 0.31872 \dots

Solution steps

4 x^{2} - 5 x = 2

Move

2

to the left side

4 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 2) = 57

x_{1, 2} = \frac{- ( - 5 ) \pm 57}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 57}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 57}{2 \cdot 4}

x = \frac{- ( - 5 ) + 57}{2 \cdot 4} : \frac{5 + 57}{8}

x = \frac{- ( - 5 ) - 57}{2 \cdot 4} : \frac{5 - 57}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

2 x^{2} + 7 x - 5 > 10

\frac{e ^{- x}}{e ^{x}}

\frac{1}{3} - 27

\frac{a}{- 3} > 4

16 s^{2} - 54 s + 35 = 0

What are the solutions to the equation 4x^2-5x=2 ?
The solutions to the equation 4x^2-5x=2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8
Find the zeros of 4x^2-5x=2
The zeros of 4x^2-5x=2 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8