What are the solutions to the equation (x+3)^2=-49 ?

The solutions to the equation (x+3)^2=-49 are x=7i-3,x=-7i-3

Find the zeros of (x+3)^2=-49

The zeros of (x+3)^2=-49 are x=7i-3,x=-7i-3

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(x + 3)^{2} = - 49

x = 7 i - 3, x = - 7 i - 3

Solution steps

(x + 3)^{2} = - 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 49 : x = 7 i - 3

Solve

x + 3 = - - 49 : x = - 7 i - 3

The solutions to the quadratic equation are:

x = 7 i - 3, x = - 7 i - 3

3 c^{3} - 6 c

x^{2} - 5 x + 6 \leq 0

\frac{180}{π} \cdot \frac{5 π}{6}

\frac{p - 15}{2} < 1 or p - 1 \geq 18

\frac{5}{6}

What are the solutions to the equation (x+3)^2=-49 ?
The solutions to the equation (x+3)^2=-49 are x=7i-3,x=-7i-3
Find the zeros of (x+3)^2=-49
The zeros of (x+3)^2=-49 are x=7i-3,x=-7i-3