What are the solutions to the equation (x-2)(2x-13)=-4 ?

The solutions to the equation (x-2)(2x-13)=-4 are x=6,x= 5/2

Find the zeros of (x-2)(2x-13)=-4

The zeros of (x-2)(2x-13)=-4 are x=6,x= 5/2

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(x - 2) (2 x - 13) = - 4

x = 6, x = \frac{5}{2}

Decimal Notation

x = 6, x = 2.5

Solution steps

(x - 2) (2 x - 13) = - 4

Expand

(x - 2) (2 x - 13) : 2 x^{2} - 17 x + 26

2 x^{2} - 17 x + 26 = - 4

Move

4

to the left side

2 x^{2} - 17 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 30}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 30 = 7

x_{1, 2} = \frac{- ( - 17 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 7}{2 \cdot 2}

x = \frac{- ( - 17 ) + 7}{2 \cdot 2} : 6

x = \frac{- ( - 17 ) - 7}{2 \cdot 2} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 6, x = \frac{5}{2}

6 x^{2} - 6 x - 36

- x + 5 + 6 x = 1 + 5 x + 3

- 324

x^{3} - 3 x^{2} - 12 x + 18

What are the solutions to the equation (x-2)(2x-13)=-4 ?
The solutions to the equation (x-2)(2x-13)=-4 are x=6,x= 5/2
Find the zeros of (x-2)(2x-13)=-4
The zeros of (x-2)(2x-13)=-4 are x=6,x= 5/2