What are the solutions to the equation x^2+14x+36=0 ?

The solutions to the equation x^2+14x+36=0 are x=-7+sqrt(13),x=-7-sqrt(13)

Find the zeros of x^2+14x+36=0

The zeros of x^2+14x+36=0 are x=-7+sqrt(13),x=-7-sqrt(13)

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x^{2} + 14 x + 36 = 0

x = - 7 + 13, x = - 7 - 13

Decimal Notation

x = - 3.39444 \dots, x = - 10.60555 \dots

Solution steps

x^{2} + 14 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 36 = 213

x_{1, 2} = \frac{- 14 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 13}{2 \cdot 1}

x = \frac{- 14 + 2 13}{2 \cdot 1} : - 7 + 13

x = \frac{- 14 - 2 13}{2 \cdot 1} : - 7 - 13

The solutions to the quadratic equation are:

x = - 7 + 13, x = - 7 - 13

(\frac{4 r ^{- 3} t ^{2}}{8 r t ^{- 1}})^{- 2}

\frac{x - 1}{1 + x} < - 2

6 (4 + 3 x) = 7 (x - 1) + 1

\frac{5}{3} \cdot \frac{2}{3}

\frac{104 i}{5 + i}

What are the solutions to the equation x^2+14x+36=0 ?
The solutions to the equation x^2+14x+36=0 are x=-7+sqrt(13),x=-7-sqrt(13)
Find the zeros of x^2+14x+36=0
The zeros of x^2+14x+36=0 are x=-7+sqrt(13),x=-7-sqrt(13)