What are the solutions to the equation -4/9 d^2+8/3 d=0 ?

The solutions to the equation -4/9 d^2+8/3 d=0 are d=0,d=6

Find the zeros of -4/9 d^2+8/3 d=0

The zeros of -4/9 d^2+8/3 d=0 are d=0,d=6

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- \frac{4}{9} d^{2} + \frac{8}{3} d = 0

d = 0, d = 6

Solution steps

- \frac{4}{9} d^{2} + \frac{8}{3} d = 0

Find Least Common Multiplier of

9, 3 : 9

Multiply by LCM=

9

- \frac{4}{9} d^{2} \cdot 9 + \frac{8}{3} d \cdot 9 = 0 \cdot 9

Simplify

- 4 d^{2} + 24 d = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

2 4^{2} - 4 (- 4) \cdot 0 = 24

d_{1, 2} = \frac{- 24 \pm 24}{2 ( - 4 )}

Separate the solutions

d_{1} = \frac{- 24 + 24}{2 ( - 4 )}, d_{2} = \frac{- 24 - 24}{2 ( - 4 )}

d = \frac{- 24 + 24}{2 ( - 4 )} : 0

d = \frac{- 24 - 24}{2 ( - 4 )} : 6

The solutions to the quadratic equation are:

d = 0, d = 6

- 3 + 3 i

(x - 2)^{2} = 21

4 x - 6 = 0

\frac{( x + 8 ) ( x - 6 )}{x - 1} \geq 0

x^{2} + 8 x + 1 = 0

What are the solutions to the equation -4/9 d^2+8/3 d=0 ?
The solutions to the equation -4/9 d^2+8/3 d=0 are d=0,d=6
Find the zeros of -4/9 d^2+8/3 d=0
The zeros of -4/9 d^2+8/3 d=0 are d=0,d=6