What is factor n^2+3n-18 ?

The solution to factor n^2+3n-18 is (n-3)(n+6)

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factor n^2+3n-18

factor

n^{2} + 3 n - 18

(n - 3) (n + 6)

Solution steps

n^{2} + 3 n - 18

Break the expression into groups

= (n^{2} - 3 n) + (6 n - 18)

Factor out

n

from

n^{2} - 3 n : n (n - 3)

Factor out

6

from

6 n - 18 : 6 (n - 3)

= n (n - 3) + 6 (n - 3)

Factor out common term

n - 3

= (n - 3) (n + 6)

\frac{1}{∣ x - 3 ∣} \geq 4

x^{2} - 16 x + 53 = 0

1.75 + 1.5 m = 28.75

0 = x^{2} - 2 x + 2

\frac{4}{∣ x ∣ + 1} \leq ∣ x ∣ + 1