What are the solutions to the equation 7m^2-2m=10 ?

The solutions to the equation 7m^2-2m=10 are m=(1+sqrt(71))/7 ,m=(1-sqrt(71))/7

Find the zeros of 7m^2-2m=10

The zeros of 7m^2-2m=10 are m=(1+sqrt(71))/7 ,m=(1-sqrt(71))/7

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7 m^{2} - 2 m = 10

m = \frac{1 + 71}{7}, m = \frac{1 - 71}{7}

Decimal Notation

m = 1.34659 \dots, m = - 1.06087 \dots

Solution steps

7 m^{2} - 2 m = 10

Move

10

to the left side

7 m^{2} - 2 m - 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 10 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 10) = 271

m_{1, 2} = \frac{- ( - 2 ) \pm 2 71}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 71}{2 \cdot 7}, m_{2} = \frac{- ( - 2 ) - 2 71}{2 \cdot 7}

m = \frac{- ( - 2 ) + 2 71}{2 \cdot 7} : \frac{1 + 71}{7}

m = \frac{- ( - 2 ) - 2 71}{2 \cdot 7} : \frac{1 - 71}{7}

The solutions to the quadratic equation are:

m = \frac{1 + 71}{7}, m = \frac{1 - 71}{7}

4 x - 12 \geq 8

13 n - 12 n = 18 + 22

z^{2} + 4 z - 5 = 0

(2^{- 3})^{2}

\frac{2 x - 8}{x + 1} \leq 1

What are the solutions to the equation 7m^2-2m=10 ?
The solutions to the equation 7m^2-2m=10 are m=(1+sqrt(71))/7 ,m=(1-sqrt(71))/7
Find the zeros of 7m^2-2m=10
The zeros of 7m^2-2m=10 are m=(1+sqrt(71))/7 ,m=(1-sqrt(71))/7